lost and found ( for me ? ): dictionary

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small tips

>>> a = {}

>>> b = {'a':3}

>>> c = {'b':4}

>>> b

{'a': 3}

>>> c

{'b': 4}

>>> a.update(b)

>>> a.update(c)

>>> a

{'a': 3, 'b': 4}

Reference

http://stackoverflow.com/questions/1915564/python-convert-a-dictionary-to-a-sorted-list-by-value-instead-of-key

Small tips.

Here is how to sort dictionary by values

sample script

# cat sort_dict_by_value.py

#!/usr/bin/env python

from operator import itemgetter

dict = {"a":860, "b":12, "c":1200, "d":100, "e":1}

for i in sorted(dict.items(), key=itemgetter(1), reverse=True):

print i

output

# ./sort_dict_by_value.py

('c', 1200)

('a', 860)

('d', 100)

('b', 12)

('e', 1)

itemgetter()

>>> from operator import itemgetter

>>> itemgetter(1)('abcdefg')

'b'

>>> itemgetter(1,5)('abcdefg')

('b', 'f')